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30 July, 12:04

After completing a study, Orlando International Airport managers concluded that the time needed to get passengers loaded on an airplane is normally distributed with a mean equal to 22.5 minutes and a standard deviation equal to 5.25 minutes. Recently one airplane required 33 minutes to get passengers on board and ready for takeoff. Find the probability that a flight will take 33 or more minutes to get passengers loaded.

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  1. 30 July, 14:34
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    Probability = 0.0228

    Step-by-step explanation:

    Let X be a random variable which is a measure of the time to get a passenger on board.

    Mean (u) = 22.5mins

    Standard deviation (s) = 5.25mins

    X = 33mins

    From Pr (X>33), starting from Pr (X = 33)

    For normal distribution, Z = 7 (X - u) / s

    Z = (33 - 22.5) / 5.25

    = 10.5/5.25

    = 2

    From the normal distribution table, 2 = 0.4772

    Recall that

    If Z is positive,

    Pr (x>a) = 0.5 - table value

    Pr (x
    Therefore;

    Pr (X>33) = 0.5 - 04772

    = 0.0228
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