A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd. What is the area of the region inside the rectangle that surrounds the square?

Question

Mathematics

Ty Hickman

2 September, 09:08

A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd. What is the area of the region inside the rectangle that surrounds the square?

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Answers (1)

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Landen Shaffer · Answer 1

Answer: 162 sq. yds.

Step-by-step explanation:

Given : A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd.

Then, Area of rectangle = length x width

= 11 yd x 17 yd = 187 sq. yds.

Area of square = (side) ²

= (5 yd) ² = 25 sq. yds.

Now, the area of the region inside the rectangle that surrounds the square will be Area of rectangle - Area of square

= 187 sq. yds. - 25 sq. yds.

=162 sq. yds.

Hence, the area of the region inside the rectangle that surrounds the square is 162 sq. yds ...