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11 November, 22:31

Three printing presses, R, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take R, working alone at its constant rate, to do the same job?

A. 8

B. 10

C. 12

D. 15

E. 20

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  1. 12 November, 01:45
    0
    20 (E)

    Step-by-step explanation:

    Printing press R, S and T are working together at their respective constant rate.

    They can do a job for 4 hours.

    Let r, s and t be the time for printing press R, S and T to complete the job alone at their respective constant rate.

    Rate of printing press R = 1/r

    Rate of printing press S = 1/s

    Rate of printing press T = 1/t

    Rate = job / time

    R + S + T = 4

    1/r + 1/s + 1/t = 1/4

    S + T = 5

    1/s + 1/t = 1/5

    Substitute 1/s + 1/t = 1/5 in the equation 1/r + 1/s + 1/t = 1/4

    1/r + 1/5 = 1/4

    1/r = 1/4 - 1/5

    1/r = (5 - 4) / 20

    1/r = 1/20

    r = 20 hours

    It takes the printing press R 20 hours to complete the job alone
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