Ask Question
16 January, 14:18

The amount of carbon-14 (_6^14text (C)) in a wooden artifact is measured to be 12.5 percent the amount in a fresh sample of wood from the same region. The half-life of carbon-14 is 5715 years. Assuming the same amount of carbon-14 was initially present in the artifact, determine the age of the artifact.

+2
Answers (1)
  1. 16 January, 17:23
    0
    17145 years

    Step-by-step explanation:

    Let n be the quantity of carbon-14 in the wooden artifact and n₀ be the quantity in the fresh sample of wood. The percentage of carbon - 14 in the wooden artifact = 12.5%. This implies that n/n₀ = 12.5/100 = 0.125

    For the carbon-14 to decay to 12.5% of its original value, it takes

    (1/2) ⁿ have lives which equals 0.125

    (1/2) ⁿ = 0.125 = 125/1000 = 1/8 = 1/2³

    So, n = 3. It becomes 12.5% after three half lives.

    So the original age of the artifact = 3 * half - life = 3 * 5715 = 17145 years
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The amount of carbon-14 (_6^14text (C)) in a wooden artifact is measured to be 12.5 percent the amount in a fresh sample of wood from the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers