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Alonso Kidd
20 September, 12:16
Quadratic formula for 2x^+5x-7
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Heath Lynch
20 September, 14:04
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x = - (7/2) ^ (1/6) or x = (7/2) ^ (1/6) or x = - (-1) ^ (1/3) (7/2) ^ (1/6) or x = (-1) ^ (1/3) (7/2) ^ (1/6) or x = - (-1) ^ (2/3) (7/2) ^ (1/6) or x = (-1) ^ (2/3) (7/2) ^ (1/6)
Step-by-step explanation:
Solve for x:
2 x^6 - 7 = 0
Add 7 to both sides:
2 x^6 = 7
Divide both sides by 2:
x^6 = 7/2
Taking 6^th roots gives (7/2) ^ (1/6) times the 6^th roots of unity:
Answer: x = - (7/2) ^ (1/6) or x = (7/2) ^ (1/6) or x = - (-1) ^ (1/3) (7/2) ^ (1/6) or x = (-1) ^ (1/3) (7/2) ^ (1/6) or x = - (-1) ^ (2/3) (7/2) ^ (1/6) or x = (-1) ^ (2/3) (7/2) ^ (1/6)
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