Given a square with two vertices of one side located at - 5,-3 and - 5,12 in square units what is its area

225 units squared

Step-by-step explanation:

Lets find the distance (the side length of the square)

D=sqrt ((x2-x1) ^ (2) + (y2-y1) ^ (2))

plug in the coordinates:

D=sqrt ((-5 - (-5)) ^ (2) + (12 - (-3)) ^ (2))

D=sqrt (0^ (2) + 15^ (2))

D=sqrt (15^ (2))

D=15

Area of a square is side length squared

A=s^2

A=15^2

A=225 units squared