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15 January, 02:55

The perimeter of a rectangle is 200 meters. If the width is 25% of the length, find the dimensions of the rectangle

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  1. 15 January, 03:24
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    The rectangle dimensions are 20 m by 80 m

    Step-by-step explanation:

    Let W represent the width and L the length. Then W = 0.25L.

    The perimeter, P, is 200 m. The formula for that is P = 2W + 2L.

    Substituting 0.25L for W, we get:

    2 (0.25L) + 2L = 200 m, or (after mult. both sides by 2) : L + 4L = 400 m

    Then 5L = 400 m, and L = 80 m. Thus, W = 0.25 (80 m) = 20 m.

    The rectangle dimensions are 20 m by 80 m
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