Ask Question
3 June, 00:45

A switchboard display in the store allows a customer to hook together any selection of components (consisting of one of each type). Use the product rules to answer the following questions:a. In how many ways can one component of each type beselected? b. In how many ways can components be selected if boththe receiver and the compact disc player are to be Sony? c. In how many ways can components be selected if none isto be Sony? d. In how many ways can a selection be made if at least oneSony component is to be included? e. If someone flips switches on the selection in a completelyrandom fashion, what is the probability that thesystem selected contains at least one Sony component? Exactly one Sony component?

+5
Answers (1)
  1. 3 June, 03:54
    0
    Question:

    A stereo store is offering a special price on a complete set of

    components (receiver, compact disc player, speakers, cassette

    deck). A purchaser is offered a choice of manufacturer for each

    component:

    Receiver: Kenwood, Sony, Sherwood

    Compact disc player: Onkyo, Pioneer, Sony, Technics

    Speakers: Boston, Infinity, Polk

    Turn table: Onkyo, Sony, Teac, Technics

    Answer:

    The answers to the questions are;

    (a) 144

    (b) 12

    (c) 54

    (d) 90

    (e) 0.625, 0.4375

    Step-by-step explanation:

    We apply the multiplication rule to solve questions (a) to (d) as follows

    a. In how many ways can one component of each type beselected?

    Receiver = 3 ways

    Compact disc = 4 ways

    Speaker = 3 ways and

    Turn table = 4 ways

    Therefore we have

    One component of each can be selected in

    3 * 4 * 3 * 4 = 144 ways

    Answer = 144 ways

    b. In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

    If the receiver MUST be Sony then that is one way out of 4

    Similarly too for the compact disc player.

    Therefore we have the following ways

    1*1*3*4 = 12

    Answer = 12 ways

    c. In how many ways can components be selected if none is to be Sony?

    If NONE is to be Sony, we then have to exclude Sony in our calculations as follows

    Receiver becomes 2 ways

    Compact disc is then 3 ways

    Speaker remains the same 3 because no Sony there and

    Turn table becomes 3

    Therefore we have

    2*3*3*3 = 54

    Answer = 54 ways

    d. In how many ways can a selection be made if at least one Sony component is to be included?

    Here, we use the logic that if at least one is to be Sony then

    (The number of ways of selecting one component) - (The number of ways where none is Sony)

    = 144 - 54 = 90

    Answer = 90 ways

    e. If someone flips switches on the selection in a completelyrandom fashion, what is the probability that thesystem selected contains at least one Sony component?

    The probability is (Number of required outcomes) : (Number of possible outcomes) = 90/144 = 0.625

    Answer = 0.625

    Exactly one Sony component?

    Here again we have

    If the receiver MUST be Sony then

    1*3*3*3 = 27

    If the compact disc MUST be Sony we have after removing Sony from receiver and turn table

    2*1*3*3 = 18

    Similarly, if the turn table MUST be Sony, then after removing Sony from the receiver and compact disc

    2*3*3=18

    Total number of ways = 63

    Probability = 63/144 = 0.4375
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A switchboard display in the store allows a customer to hook together any selection of components (consisting of one of each type). Use the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers