Solve the Quadratics:

1) k^2-8k=0

2) a^2+5a=0

3) 6n^2+5n-25=0

4) 2x^2-11x-21=0

5) 2n^2+13n+19=4

Bonus Word Problem:

The larger leg of a right triangle is 7cm longer than its smaller leg. The hypotenuse is 8cm longer than the small leg. How many centimeters long is the smaller leg?

Step-by-step explanation:

1) k²-8k = 0

k (k-8) = 0

k = 0 or k=8

2) a²+5a=0

a (a+5) = 0

a=0 or a = - 5

3) 6n²+5n-25=0

delta = b²-4ac b = 5 and a = 6 and c = - 25

delta = 5²-4 (6) (-25) = 625 = 25²

n 1 = (-5+25) / 12 = 20/12 = 5/3

n 2 = (-5-25) / 12 = - 30/12 = - 5/2

same method for 4) and 5)