Assume a color display using 8 bits for each of the primary colors (red, green, blue) per pixel and a frame size of 1280 * 1024. What is the minimum size in bytes of the frame buffer to store a frame?

-8bits is equivalent yo 1 byte

-bit is (0 or 1)

So each pixel requires 3 bytes

Primary colors are RGB (red, green and blue), so each color represent one byte.

The frame size is:

1280*1024=1310720 pixels

So that the frame contained 1310720 pixels

The size of the frame buffer is equal to the product of RGB and frame pixels:

=3 * 1310720

=3932160 bytes