Solve the following systems using substitution.

X - 9y = 25

6x - 5y = 3

x = - 2, y = - 3

Step-by-step explanation:

Multiply eqn1 by the LCM of 1 and 6 i. e coefficients of x

We get:

6x - 54y = 150 (eqn1)

6x - 5y = 3 (eqn2)

- 49y = 147

y = 147

-49

y = - 3

Substitute y in eqn2

6x - 5 (-3) = 3

6x + 15 = 3

6x = - 12

x = - 2