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11 June, 22:35

What is the first step in writing f (x) = 6x2 + 5 - 42x in vertex form?

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  1. 12 June, 02:15
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    The first step in writing f (x) = 6x^2 + 5 - 42x in vertex form is to put it into proper quadratic form and then finding the axis of symmetry. Proper quadratic form is ax^2 + bx + c. The formula to find the axis of symmetry is - b over 2a.
  2. 12 June, 02:26
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    Back to seeks out of the first two times
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