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28 February, 02:15

Which quadratic function has one real solution?

0 = 2 (x + 7) (x - 5)

0 = (x - 3) (x - 3) The quadratic function f (x) = - x2 - 6x - 8 is graphed.

What are the solutions of the quadratic equation 0 = - x2 - 6x - 8?

2 and - 4

-2 and 4

-2 and - 4

2 and 4

0 = 2.4 (x - 2) (x + 2)

0 = (x - 2) (x - 1)

+2
Answers (1)
  1. 28 February, 03:10
    0
    Step-by-step explanation:

    ans will be 12 X will be the ans
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