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11 June, 21:11

Solve the following system of equations algebraically and check.

y=x^2+3x+4

y-x=7

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  1. 12 June, 00:50
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    Y=x^2+3x+4

    y-x=7

    x^2+3x+4-x=7

    x^2+2x+4=7

    (factor) x^2+2x-3=0

    (x+3) (x-1) = 0

    X = - 3 and X=1

    (Plug x in for y)

    Y = 1^2+3 (1) + 4

    Y=8

    (Check your answer on the second equation)

    8-1=7

    7=7 (Which is the solution)
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