The lengths of the legs of a right triangle are consecutive even integers. The hypotenuse is 58 inches. What is the sum of the lengths of the legs in inches?

82 inches

Step-by-step explanation:

The difference between consecutive even integers is 2, thus

let the legs be n and n + 2

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

n² + (n + 2) ² = 58² ← expand and simplify left side

n² + n² + 4n + 4 = 3364 (subtract 3364 from both sides)

2n² + 4n - 3360 = 0 (divide all terms by 2)

n² + 2n - 1680 = 0 ← in standard form

(n + 42) (n - 40) = 0 ← in factored form

Equate each factor to zero and solve for n

n + 42 = 0 ⇒ n = - 42

n - 40 = 0 ⇒ n = 40

But n > 0 ⇒ n = 40

and n + 2 = 40 + 2 = 42

Thus sum of legs = 40 + 42 = 82 inches