a bag has more green balls than blue balls and there is at least one blue ball. let b represent the number of blue balls and let g represent the number of green balls.

2) 2 b < b + g

Step-by-step explanation:

Here, the given question is incomplete.

A bag has more green balls than blue balls, and there is at least one blue ball.

Let b represent the number of blue balls and let g represent the number of green balls.

Let's compare the expressions 2 b and b + g. Choose the correct statement?

1. 2 b > b + g

2. 2 b < b + g

3. 2 b = b + g

4. There is not enough information to tell.

Now, here given:

b: the number of blue balls

g: the number of green balls

Also, the number of green balls is greater than blue balls.

⇒ g > b

Also, b ≥ 1 as the blue ball is one or more in number.

Now, as b is at least one.

So, g being more than b, we get: b ≥ 2

So, from given equations, we get:

g > b

b ≥ 2

Adding the respective sides, we get:

g + b ≥ 2 + b

or, 2 b < b + g