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20 June, 05:00

Given the function f (x) = 3x + 1, evaluate f (a + 1). 3 a + 2 3 a + 4 3 a + 1

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  1. 20 June, 07:22
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    f (a + 1) = 3a + 4

    Step-by-step explanation:

    Given the function is:

    f (x) = 3x + 1

    To determine f (a + 1) we have to substitute (a + 1) in place of 'x'.

    Therefore, we have:

    f (a + 1) = 3 (a + 1) + 1

    = 3a + 3 + 1

    = 3a + 4

    ['a' could be any real number.]

    So, f (a + 1) = 3a + 4 is the answer.
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