Yochanon walked from home to the bus stop at an average speed of 5mph. He immediatly got on his school bus and traveled at an average speed of 60mph until he got to school. The total distance from his home to school is 35 miles, and the entire trip took 1.5 hours.

Question

Mathematics

Guest

17 May, 17:33

Yochanon walked from home to the bus stop at an average speed of 5mph. He immediatly got on his school bus and traveled at an average speed of 60mph until he got to school. The total distance from his home to school is 35 miles, and the entire trip took 1.5 hours.

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Answers (1)

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Cullen Bishop · Answer 1

He walked 5 miles in 1 hour and travelled for 30 miles in 1/2 an hour.

Step-by-step explanation:

I guess you want to know for how long he walked and/or how long he rode the bus.

Assume he walked x miles so he travelled by bus (35 - x) miles.

Then the time he walked can be found from

5 = x / t so t = x/5.

Then the time he travelled by bus = (1.5 - t) = (35 - x) / 60.

Therefore from the last 2 equations

x/5 + (35 - x) / 60 = 1.5 Multiply through by 60:

12x + 35 - x = 90

11x = 55

x = 5 = the distance he walked and he walked this in 5/5 = 1 hour.

The time he travelled by bus is 0.5 hours and the distance is 35-5 = 30 miles.