The sum of two integers is 64. The larger is 16 more than three times the smaller. Find the two integers.

12 and 52

Step-by-step explanation:

Let x and y be the 2 integers with x > y, then

x + y = 64 and

x = 3y + 16 (16 more than 3 times the smaller)

Substitute x = 3y + 16 into x + y = 64, that is

3y + 16 + y = 64

4y + 16 = 64 (subtract 16 from both sides)

4y = 48 (divide both sides by 4)

y = 12 and x = 3 (12) + 16 = 36 + 16 = 52

The 2 integers are 12 and 52