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20 October, 12:43

Luiza João tem juntos R$123 se Luiz tivesse a mais metade da quantia que tem mais um real teria dobro de João quanto tem cada um

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  1. 20 October, 14:11
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    A=25

    B=98

    Step-by-step explanation:

    You can see it as a 2-eq system.

    Call A Joao's money and B Luiz's money. The sum is $123:

    A + B = 123

    As the half of Luiz's money + 1 is the double of Joao's money, we could represent this as:

    (B/2) + 1 = 2A [this is what the last sentence says]

    We can get the A value by dividing both sides by 2:

    [ (B/2) + 1]/2 = 2A / 2

    B/4 + 1/2 = A

    Then, replacing this A value on our first equation:

    B/4 + 1/2 + B = 123

    B/4 + 4B/4 = 123 - 1/2

    (5/4) B = 122.5

    Multiplying by (4/5) [or dividing by 5/4] to eliminate this 5/4:

    (5/4) B * (4/5) = 122.5 (4/5)

    B = 98

    Then we find A:

    A = B/4 + 1/2 = 24.5 + 0.5 = 25

    A=25
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