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12 June, 21:09

Find two complex numbers whose sum is 12 and whose product is 37.

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  1. 12 June, 21:15
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    6 ± i and 6 ± i

    Step-by-step explanation:

    Let x be the first number.

    Let y be the second number.

    x + y = 12

    x * y = 37

    Solve for x in the first equation.

    x = 12 - y

    Put x as 12-y in the second equation and solve for y.

    (12 - y) y = 37

    12y - y² = 37

    - y² + 12y - 37 = 0

    y = 6 ± i

    Put y as 6 ± i in the first equation and solve for x.

    x + 6 ± i = 12

    x = 12 - 6 ± i

    x = 6 ± i
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