Find the equation of the line which is perpendicular 10y + 5x = 3 and passes through (-7,-1)

P. s. working.

y = 2x + 13

Step-by-step explanation:

when 2 lines are perpendicular, the product of the two gradients is - 1

i. e. m x m1 = - 1

so from 10y + 5x = 3, the gradient m is - 0.5

m1 = - 1 / - 0.5 = 2

using m1 = 2 and pt (-7,-1),

the eqn is y = (m1) x + c

-1 = 2 (-7) + c

c = 13

thus y = 2x + 13