What is the slope of a line with coordinates (5,3) and (1,2) ?

A (1,4)

B 4

C (1,2)

Slope (m) =

ΔY

ΔX

=

1

4

= 0.25

θ =

arctan (ΔY) + 180°

ΔX

= 194.03624346793°

ΔX = 1 - 5 = - 4

ΔY = 2 - 3 = - 1

Distance (d) = √ΔX2 + ΔY2 = √17 = 4.1231056256177

Equation of the line:

y = 0.25x + 1.75

or

y =

1 x

4

+ 7

4

When x=0, y = 1.75

When y=0, x = - 7

1/4

Step-by-step explanation:

m = (y2-y1) / (x2-x1)

m = (2-3) / (1-5)

m=-1/-4

m=1/4