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22 May, 11:03

100

10, UUS

11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20

meters above the ground. The height h (in meters) of the ball at time t in seconds) after it

is thrown can be found by h (t) = - 5t^2 + 15t + 20. Find the time when the ball is again 20

meters above the ground.

A

1 second

(B

2 seconds

C

3 seconds

D

4 seconds

+5
Answers (1)
  1. 22 May, 13:41
    0
    The correct answer is B
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