A 560-g squirrel with a surface area of 930 cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a drag coefficient for a horizontal skydiver.) What will be the velocity of a 56-kg person hitting the ground, assuming no drag contribution in such a short distance

vf = 9.9 m/s

v_r = 13.9 m/s

Step-by-step explanation:

Given

m = 560 g

A (t) = 930 cm ² = 0.93 m²

h = 5 m

C = 1

m_2 = 56 Kg / m³

ρ = 1.21 kg

g = 9.8

Terminal Velocity = v_r = ?

Final velocity = v_f = ?

Solution:

Surface tension facing the fluid

A_f = A (t) / 2 = 0.93/2 = 0.47 m²

Terminal velocity is given by

v_r = √ ((2 x m x g) / (ρ x C x A_f))

v_r = √ (2 x 0.56 x 9.8) / (1.21 x 1 x 0.47)

v_r = 13.9 m/s

Now final Velocity

vf² = vi² + 2 x h x g

vi = 0

vf = √ (2 x 5 x 9.8)

vf = 9.9