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6 October, 15:08

How many solutions for linear equation 3x + 5y = 25 can be found so that - 20 < y < 10, and x is an integer?

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  1. 6 October, 17:12
    0
    50

    Step-by-step explanation:

    3x = 25 - 5y

    -100 < 5y < 50

    -50 < - 5y < 100

    -25 < 25 - 5y < 125

    -8.333 < x < 41.667

    41+8+1 = 50
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