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17 August, 14:23

If f (2x-1) = x+2, then what is the value of f⁻¹ (2x-1) ?

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  1. 17 August, 16:53
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    So F (x+3) = (x+3+5) / 2 = (x+8) / 2

    Step-by-step explanation:

    Given F (2x-1) = x+2

    Put 2x-1 = y=> x = (y+1) / 2

    Hence F (y) = (y+1) / 2 + 2 = (y+5) / 2

    So F (x) = (x+5) / 2

    So F (x+3) = (x+3+5) / 2 = (x+8) / 2.
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