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30 March, 05:46

Choose the inverse of y=x^2-10

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  1. 30 March, 07:04
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    x = 5 + sqrt (y+25), for x>=5

    x = 5 - sqrt (y+25), for x<=5

    Step-by-step explanation:

    y = x^2 - 10x + 25 - 25

    y = (x-5) ^2 - 25

    y+25 = (x-5) ^2

    x-5 = + / -sqrt (y+25)

    And you get TWO inverses:

    x = 5 + sqrt (y+25), for x>=5

    x = 5 - sqrt (y+25), for x<=5
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