Solve 2x+7>+x + 19

and can you do the same if 2 was 3.

2nd question is write an expression if 3 was open inequality and line continues past negative 5

Solving 2x + 7 > x + 19

2x + 7 > x + 19

Move 7 by subtracting from both sides.

2x > x + 19 - 7

2x > x + 12

Move x by subtracting from both sides.

2x - x > 12

x > 12

Therefore, x is greater than 12.

Solving 3x + 7 > x + 19

3x + 7 > x + 19

Move 7 by subtracting from both sides.

3x > x + 19 - 7

3x > x + 12

Move x by subtracting from both sides.

3x - x > 12

2x > 12

Divide 2 on both sides to get x.

2x/2 > 12/2

x > 6

Therefore, x is greater than 6.

Part 2:

Write an expression for if 3 was open inequality and line continues past negative 5. This may not be correct due to the vagueness of what it's asking.

Expression: x < - 5 < 3

x indicates all real numbers less - 5

3 is open inequality and is the greatest

The 2nd question is like really vague.

Step-by-step explanation:

Original problem:

2x + 7 > x + 19

Subtract x from both sides.

x + 7 > 19

Subtract 7 from both sides.

x > 12

Problem with 3 instead of 2.

3x + 7 > x + 19

Subtract x from both sides.

2x + 7 > 19

Subtract 7 from both sides.

2x > 12

Divide both sides by 2.

x > 6

2nd question (I'm not sure I understand it correctly.)

x < 3