April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how many adult and children tickets were sold

The adults would be 40 bucks and the kids would be 35 you are welcome u goons

Step-by-step explanation:

~First we have to write our two equations that are:

1. 8x+5y=$495 (becoz the no. of adult tickets is unknown and children is unknown we use variables instead and multiplying them with the amount of money for each gives us 495)

2. x+y=75 (No. of adult tickets and children altogether gives us 75)

~Use the substitution method by using any of the equations and putting the variable you want as the subject and then putting its values in the next equation:

x+y=75

x=75-y

~Substitute to find y (no. of children's ticket)

8x+5y=495

8 (75-y) + 5y=495

600-8y+5y=495

-8y+5y=495-600

-3y=-105

y=-105/-3

y=35

Therefore, the no. of children tickets is 35.

~Substituting y in the substitution equation (x=75-y):

x=75-35

x=40

Therefor no. of tickets sold to adults is 40.

~Final answers:

Adults=40

Children=35