What is the solution to the following system of equations?

x - 3y = 6

2x + 2y = 4

(-1, 3)

(3, - 1)

(1, - 3)

(-3, 1)

(3, - 1)

Step-by-step explanation:

Given the 2 equations

x - 3y = 6 → (1)

2x + 2y = 4 → (2)

Rearrange (1) expressing x in terms of y by adding 3y to both sides

x = 6 + 3y → (3)

Substitute x = 6 + 3y into (2)

2 (6 + 3y) + 2y = 4 ← distribute and simplify left side

12 + 6y + 2y = 4

12 + 8y = 4 (subtract 12 from both sides)

8y = - 8 (divide both sides by 8)

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 6 + 3 ( - 1) = 6 - 3 = 3

Solution is (3, - 1)