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7 November, 22:47

How do you solve the simultaneous equations?

y = x + 4

y = 2x² + 3x - 1

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Answers (1)
  1. 8 November, 01:31
    0
    (1.16, 5.16) and (-2.16, 1.84) to the nearest hundredth.

    Step-by-step explanation:

    By substitution. You substitute y = x + 4 into the second equation:

    x + 4 = 2x^2 + 3x - 1

    2x^2 + 2x - 5 = 0

    x = [ - 2 + / - sqrt (2^2 - 4*1*-5) ] / 2*2

    = - 1/2 + / 1 sqrt 24/4

    = 1.158, - 2.158

    When x = 1.158, y = 1.158 + 4 = 5.158

    When x = - 2.158, y = - 2.158 + 4 = 1.842.
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