Ask Question
26 September, 02:50

A storm dumps 1.0 cm of rain on a city 6 km wide and 8 km long in a 2-h period. How many metric tons (1 metric ton = 103 kg) of water fell on the city? (1 cm3 of water has a mass of 1 g = 10-3 kg.) How many gallons of water was this?

+5
Answers (1)
  1. 26 September, 05:25
    0
    4660194 metric ton

    126802560 gallon

    Step-by-step explanation:

    1 cm = 0.01 m

    6 km = 6000 m

    8 km = 8000 m

    Volume = 0.01 m x 6000 m x 8000 m = 480000 m³

    480000 m³ = 480000000 kg of water (density of water = 1000kg/m³)

    103 kg = 1 metric ton

    480000000 kg = 480000000 / 103 = 4660194 metric ton

    1 m³ = 264.17 gallon

    480000 m³ = 480000 x 264.172 = 126802560 gallon
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A storm dumps 1.0 cm of rain on a city 6 km wide and 8 km long in a 2-h period. How many metric tons (1 metric ton = 103 kg) of water fell ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers