Ryan buys a bag of cookies that contains 8 chocolate chip cookies, 4 peanut butter cookies, 4 sugar

cookies and 8 oatmeal cookies. What is the probability that Ryan randomly selects a peanut butter

cookie from the bag, eats it, then randomly selects a chocolate chip cookie?

4/69 to be exact. Slightly greater than 1/18

Step-by-step explanation:

The chance of selecting the PB cookie on the first try is 4 out of 24 or 1 out of 6. There are now 23 coolies left; 8 are chocolate, so 8/23 chance. (Slightly greater than 1/3) The chance of both events happening is the product if the individual events' chances. So multiply 1/6 times 8/23 to get 8/138. That reduces to 4 / 69. If he had put that first cookie back, the multiplication would have been 1/6*1/3. A lot easier.