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27 October, 23:56

Suppose that z-scores come from a standard normal distribution. Use the Normal Probability Applet (Links to an external site.) to answer this question. What proportion of the z-scores will be between - 1 and 1? (Give your answer as a decimal, accurate to three decimal places e. g. If the answer was 0.389184 you would enter 0.389)

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  1. 28 October, 02:39
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    0.683

    Step-by-step explanation:

    We have to find P (-1
    For this purpose, we use normal distribution area table

    P (-1
    Using normal area table and looking the value corresponds to 1.0, we get

    P (-1
    P (-1
    Rounding the answer to three decimal places

    P (-1
    So, 68.3% of the z-scores will be between - 1 an 1.
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