Maya has 3 times as many dimes as nickels. She has 4 more quarters than nickels. if she has a total of $9.40, how many of each type of coin does she have?

Answer: nickels = 14, dimes = 42, quarters = 18

Step-by-step explanation:

Let n represent nickels which has a value of $0.05

Let d represent dimes which has a value of $0.10

Let q represent quarters which has a value of $0.25

It is given that:

n = n

d = 3n

q = n + 4

and their total value is $9.40 ⇒ n + d + q = $9.40

Use substitution to find the quantity of nickels:

.05 (n) +.10 (3n) +.25 (n + 4) = 9.40

5n + 10 (3n) + 25 (n+4) = 940 multiplied by 100

5n + 30n + 25n + 100 = 940 distributed

60n + 100 = 940 added like terms

60n = 840 subtracted 100

n = 14 divided by 60

n = 14

d = 3n

= 3 (14)

= 42

q = n + 4

= (14) + 4

= 18