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23 February, 02:31

A projectile is launched upward from a height of 704 feet with an initial velocity of 112 ft/s. The equation gives the height h after t seconds. find the number of seconds until it returns to the ground

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  1. 23 February, 05:34
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    We are given the data ho equal to 704 feet and vo equal to 112 feet per second. We apply then kinematics equation: h = ho + vot - 1/2 gt2. Substituting to the given equation,

    h = 704 + 112t - 1/2 * 32*t2when h is equal to zero, 0 = 704 + 112t - 1/2 * 32*t2t is equal to 11 seconds
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