Ask Question
23 July, 03:02

One warehouse had 185 tons of coal, another one has 237 tons. The first warehouse delivered 15 tons of coal to its clients daily, the second one delivered 18 tons of coal to its clients daily. In how many days will the second warehouse have 1.5 times more coal than the first one?

+2
Answers (1)
  1. 23 July, 03:52
    0
    Answer: 9 days

    Step-by-step explanation:

    Converting the question above to simultaneous equations

    For warehouse 1

    X = 185 - 15d ... eqn1

    For warehouse 2

    Y = 237 - 18d ... eqn2

    From the question given, we need to find the value of d at which Y = 1.5X

    237 - 18d = 1.5 (185-15d)

    237 - 18d = 277.5 - 22.5d

    22.5d - 18d = 277.5 - 237

    4.5d = 40.5

    d = 40.5/4.5

    d = 9

    Therefore, it takes 9 days for the second warehouse have 1.5 times more coal than the first one
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “One warehouse had 185 tons of coal, another one has 237 tons. The first warehouse delivered 15 tons of coal to its clients daily, the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers