20 grams of H2S react with 20 grams of O2. What is the limiting reagent?

2H, S (g) + 302 (g)

→ 2802 (g) + 2H2O (g)

The limiting reagent is O2

Step-by-step explanation:

From the equation of reaction,

2 moles of H2S is required to react with 3 moles of O2

Therefore, 20 grams of H2S is required to react with (20*3/2 = 30 grams) of O2

30 grams of O2 is required to react with 20 grams of H2S but only 20 grams of O2 is available

Therefore, the limiting reagent (reagent in small supply) is O2