The rectangle shown has a perimeter of 34 cm and the given area. Its length is 5 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Let the width be w, then the length is 2w + 5

Perimeter = 2 (length + width)

34 = 2 (2w + 5 + w) = 2 (3w + 5)

3w + 5 = 34/2 = 17

3w = 17 - 5 = 12

w = 12/3 = 4

Therefore, the width is 4 cm and the length is 2 (4) + 5 = 8 + 5 = 13 cm.