Calculate the work associated with the expansion of a gas

from46l to64 l at

a constant external pressure of 15 atm?

-27 kJ

Step-by-step explanation:

Given data

Initial volume (Vi) : 46 L Final volume (Vf) : 64 L External pressure (P) : 15 atm

We can find the work (w) associated with the expansion of a gas using the following expression.

w = - P. ΔV

w = - P. (Vf - Vi)

w = - 15 atm. (64 L - 46 L)

w = - 270 atm. L. (101.325 J / 1 atm. L)

w = - 2.7 * 10⁴ J

w = - 27 kJ