What is the value of x in the equation below?

1+2e^x+1=9

a). x=log4-1

b) x=log4

c). x=Ln4-1

d). x=ln4

Question

Mathematics

Numbers

7 September, 07:09

What is the value of x in the equation below?

1+2e^x+1=9

a). x=log4-1

b) x=log4

c). x=Ln4-1

d). x=ln4

+5

Answers (1)

Know the Answer?

Simeon Barajas · Answer 1

Answer: C

Step-by-step explanation:

1+2e^x+1=9

2e^x+1=9-1

e^x+1 = 8/2

e^x+1 = 4

Here we can applicate the Ln:

ln e^x+1 = ln 4

Applicating the log property for exponent:

(x+1). ln e = ln 4

Ln e = 1, so:

x+1 = ln 4

x = ln 4-1

What is the value of x in the equation below?1+2e^x+1=9a). x=log4-1b) x=log4c). x=Ln4-1d). x=ln4

What is the value of x in the equation below?

1+2e^x+1=9

a). x=log4-1

b) x=log4

c). x=Ln4-1

d). x=ln4