Find the zeros of the function h (x) = x^2+23x+60 by factoring.

x = - 20, x = - 3

Step-by-step explanation:

To find the zeros, let h (x) = 0, that is

x² + 23x + 60 = 0

Consider the factors of the constant term ( + 60) which sum to give the coefficient of the x - term ( + 23)

The factors are + 20 and + 3, since

20 * 3 = 60 and 20 + 3 = 23, thus

(x + 20) (x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 20 = 0 ⇒ x = - 20

x + 3 = 0 ⇒ x = - 3