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30 May, 17:25

Use the information from the previous problem. Assume that each of the above numbers occurs once except for 33, which occurs twice, and 135, which occurs four times. Calculate the weighted average of this new list of numbers? a) 58.89b) 81.56c) 134.22d) 146.80

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  1. 30 May, 17:53
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    The question is not complete! Here is the complete question and its answer!

    Question:

    Compute the average of the following numbers: 17, 33, 45, 66, and 135.

    a) 45.00

    b) 59.20

    c) 61.67

    d) 74.00

    Use the information from the previous problem. Assume that each of the above numbers occurs once except for 33, which occurs twice, and 135, which occurs four times. Calculate the weighted average of this new list of numbers.

    a) 58.89

    b) 81.56

    c) 134.22

    c) 146.80

    Answer:

    b) 59.20

    b) 81.56

    Step-by-step explanation:

    Sum = 17 + 33 + 45 + 66 + 135

    Sum = 296/5

    Average = Sum/Total terms

    Average = 59.2

    Therefore, correct answer is (b) 59.2

    Weighted Sum = 17 + 2 (33) + 45 + 66 + 4 (135)

    or we can also write like this

    Weighted Sum = 17 + 33 + 33 + 45 + 66 + 135 + 135 + 135 + 135

    Weighted Sum = 734

    Weighted Average = Weighted Sum/Total terms

    Weighted Average = 734/9

    Weighted Average = 81.56

    Therefore, correct answer is (b) 81.56
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