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28 July, 06:12

An independent-measures research study uses a total of 18 participants to compare two treatment conditions. If the results are used to construct a 90% confidence interval for the population mean difference, then the t values will be ±1.746. a) Trueb) False

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  1. 28 July, 09:23
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    The answer is false

    Step-by-step explanation:

    In a sample above 30 obs like this the confidence interval is defined as

    X + - t * (s/sqrt (n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.

    To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level

    The significance is obtained:

    significance = 1 - confidence level = 1 - 0.9 = 0.10

    Degrees of freedom (df) for the inteval are

    df = n - 1 = 18 - 1 = 17

    So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 (thats the t for 16 df)
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