Ask Question
21 May, 20:23

5. What is the radius and center of the circle given by the equation (x+12) ^2 + (y-4) ^2=81?

+3
Answers (1)
  1. 21 May, 21:39
    0
    Center is (-12,4) and radius is 9

    Step-by-step explanation:

    Equation of circle with (h, k) as center and radius r is given by,

    (x-h) ² + (y-k) ² = r²

    Here we need to find the radius and center of the circle given by the equation (x+12) ² + (y-4) ²=81

    Changing equation to (x-h) ² + (y-k) ² = r² form

    (x+12) ² + (y-4) ²=81

    (x - (-12)) ² + (y-4) ² = 9²

    So, h = - 12, k = 4 and r = 9

    Center is (-12,4) and radius is 9
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “5. What is the radius and center of the circle given by the equation (x+12) ^2 + (y-4) ^2=81? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers