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6 March, 21:26

In how many different ways can robert order 3 objects from a set of 8 objects?

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  1. 6 March, 23:29
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    Step-by-step explanation:

    If the order of the objects doesn't matter (ABC is considered the same as CBA), then the number of combinations is:

    ₈C₃ = 8! / (3! (8-3) !) = 56

    If the order does matter (ABC is considered different than CBA), then the number of permutations is:

    ₈P₃ = 8! / (8-3) ! = 336
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