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5 September, 09:35

Steve thinks that he has a fair coin with equal probability of landing head or tails. He is ready to change his mind if in a long enough series of flips the coin will land on the same side. Steve decided that "long enough" means the probability of a fair coin landing the same way is less than 1%. What is the shortest series that will allow Steve to declare that the coin is not fair?

A. 7 flips

B. 8 flips

C. 99 flips

D. 101 flips

Maybe C idk

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Answers (1)
  1. 5 September, 11:18
    0
    Answer: A. 7 flips

    Step-by-step explanation:

    the shortest series that will allow Steve to declare that the coin is not fair = n

    The probability of a coin tossed n times to land on the same side is given as;

    Pn = 1/2^n

    For Pn < 1% = 0.01

    1/2^n < 0.01

    nLog (1/2) < Log (0.01)

    n > Log (0.01) / Log (1/2)

    n > 6.64

    The shortest n = 7

    Therefore, the shortest series that will allow Steve to declare that the coin is not fair

    = 7 flips.
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