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2 March, 10:35

3. Could the circle with equation x^2-6x+y^2-7=0 have a radius of 4? Why or why not?

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  1. 2 March, 11:41
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    Answer: Yes, it has a radius of 4

    Step-by-step explanation:

    General equation of a circle is

    x²+y²+2gx+2fy+c = 0 ... 1

    Where r = √g²+f²-c

    Comparing the general b equation to the given equation to get g, f and c

    x^2-6x+y^2-7=0

    Rearranging

    x²+y²-6x - 7 = 0 ... 2

    Comparing 1 and 2;

    2gx = - 6x

    2g = - 6

    g = - 3

    2fy = 0 (since there is no function of y in the given equation)

    f = 0

    c = - 7

    Substituting into the radius formula

    r = √ (-3) ²+0² - (-7)

    r = √9+7

    r = √16 units

    r = 4units

    It is true that the radius of the circle is 4units
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