Ask Question
13 December, 09:19

A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.63 m/s. Four seconds later, the bicyclist hops on his bike and accelerates at 2.11 m/s2 until he catches his friend. How much time does it take until he catches his friend

+5
Answers (1)
  1. 13 December, 11:17
    0
    From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s) * t.

    The bicyclist covers a distance of 1/2 * (2.11 m/s^2) * t^2. They meet when these distances are equal:

    3.63 t = 1.055 t^2 = => 1.055 t^2 - 3.63 t = 0

    ==> t = 0 s or t = 3.44 s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.63 m/s. Four seconds later, the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers